Trigonometric Reduction & Related Angles Calculator

Trigonometric Reduction & Related Angles Calculator sin(π − α), cos(−α)

Enter any angle in degrees or radians (150°, 225°, 7π/6, −750°…). The tool removes full turns, locates the terminal point on the unit circle and its quadrant, picks the right related-angle formula to reduce it to an acute angle α ∈ [0; π/2], and shows the exact values of sin, cos, tan and cot step by step.

📘 How to use
  1. Enter an angle: degrees (150, 225°, -750, 22.5) or radians with π (7pi/6, 7π/6, -3pi/4). A bare number is read using the Bare numbers are setting.
  2. Choose a function or keep All 4 functions, then click Reduce step by step. The solution includes a unit-circle figure marking the terminal point M and the acute angle α.
  3. Related-angle table: see the five formula groups with memory aids and a table of special-angle values from 0 to 2π. Click 🧮 Try to open an example in the calculator.
  4. Every solution can be copied, printed or shared by link. Click VI / EN to switch the tool language instantly.
Preview:

💡 An angle containing π is always read as radians, and an angle with ° is always degrees. When the acute angle α is a multiple of 15° (π/12) the result is an exact surd; other angles give decimal approximations.

The tool above reduces any trigonometric angle, including negative angles and angles larger than a full turn, to an acute angle α ∈ [0; π/2], then reads sin, cos, tan and cot from the special-angle table. The Reduce an angle tab shows all five steps: read the angle, remove full turns, locate the terminal point and its quadrant, choose the related-angle formula and substitute the values, together with a unit-circle figure. The Related-angle table tab summarises the five formula groups and the values of the special angles from 0 to 2π. Below is the theory: each related-angle group comes with its formulas, a memory aid and one fully worked example. The article ends with a 5-question quiz and 5 advanced practice exercises.

Unit circle with the terminal point M of α and the terminal points of its five related angles: −α mirrored across the x-axis, π − α across the y-axis, π/2 − α across the line y = x, α + π through the origin, and α + π/2 as M rotated by 90°.y = xxyOαMM₁M₂M₃M₄M₅M: angle αstarting point, α is acuteM₁: angle −αmirror across x-axis → cos staysM₂: angle π − αmirror across y-axis → sin staysM₃: angle π/2 − αmirror across y = x → co-functionsM₄: angle α + πthrough the origin → tan, cot stayM₅: angle α + π/2M rotated 90° → sin becomes cos
Each related angle matches a symmetry of the terminal point M: a reflection across the x-axis (opposite), across the y-axis (supplementary), across the line y = x (complementary), through the origin (differing by π) or a 90° rotation (differing by π/2). The coordinates of the image point give the formula at once.

🧭 Three steps to reduce any angle to an acute angle

  1. Remove full turns. Write θ = θ₀ + k·2π (or θ₀ + k·360°) with 0 ≤ θ₀ < 2π and k an integer. Sine and cosine have period 2π, tangent and cotangent have period π, so θ and θ₀ share every trigonometric value.
  2. Find the quadrant of the terminal point M of θ₀ to get the signs. Memory aid “All Students Take Calculus”: in quadrant I all values are positive, in II only sine, in III only tangent and cotangent, in IV only cosine.
  3. Choose the related angle that gives an acute α: in quadrant II write θ₀ = π − α (supplementary), in quadrant III write θ₀ = π + α (differing by π), in quadrant IV write θ₀ = 2π − α, which has the same values as −α (opposite).
sin(α + k2π) = sin α, cos(α + k2π) = cos α
tan(α + kπ) = tan α, cot(α + kπ) = cot α

Quick example. 2010° = 210° + 5·360°, and 210° lies in quadrant III with 210° = 180° + 30°. Therefore:

sin 2010° = −1/2

💡 Memory aid: “cosine ignores the minus, sine survives the supplement, co-functions cross over, tangent repeats every π”

  • Opposite angles: cos(−α) = cos α.
  • Supplementary angles: sin(π − α) = sin α.
  • Complementary angles: sine and cosine swap, tangent and cotangent swap.
  • Angles differing by π: tangent and cotangent are unchanged.
  • Angles differing by π/2: the sine of the larger angle is the cosine of the smaller, the cosine of the larger is minus the sine of the smaller.

Any function the rhyme does not keep changes sign. Complementary angles only swap functions and never change sign.

↔️ 1. Opposite angles: α and −α (“cosine ignores the minus”)

The terminal points of α and −α are mirror images across the x-axis: same x-coordinate, opposite y-coordinates. The x-coordinate is the cosine and the y-coordinate is the sine, so cosine stays while sine changes sign; tangent and cotangent are quotients of sine and cosine, so they change sign too. In other words, cosine is an even function, while sine, tangent and cotangent are odd.

cos(−α) = cos α, sin(−α) = −sin α
tan(−α) = −tan α, cot(−α) = −cot α

Example 1. Compute A = cos(−π/3) + sin(−π/6).

  1. Cosine is even, drop the minus: cos(−π/3) = 1/2.
  2. Sine is odd, pull the minus out: sin(−π/6) = −1/2.
  3. Add up:
A = 0

🪞 2. Supplementary angles: α and π − α (“sine survives the supplement”)

The terminal points of α and π − α are mirror images across the y-axis: same y-coordinate, opposite x-coordinates. So sine stays while cosine changes sign, and tangent and cotangent follow cosine. These are the formulas for every angle in quadrant II: write θ = π − α (or 180° − α).

sin(π − α) = sin α, cos(π − α) = −cos α
tan(π − α) = −tan α, cot(π − α) = −cot α

Example 2. Compute B = sin(2π/3) · cos(5π/6).

  1. 2π/3 = π − π/3, and sine survives: sin(2π/3) = √3/2.
  2. 5π/6 = π − π/6, and cosine changes sign: cos(5π/6) = −√3/2.
  3. Multiply:
B = −3/4

✖️ 3. Complementary angles: α and π/2 − α (“co-functions cross over”)

The terminal points of α and π/2 − α are mirror images across the line y = x, so the x-coordinate of one is the y-coordinate of the other: sine and cosine swap, tangent and cotangent swap, and no minus sign appears. This is where the name “cosine” comes from: the sine of the complement.

sin(π/2 − α) = cos α, cos(π/2 − α) = sin α
tan(π/2 − α) = cot α, cot(π/2 − α) = tan α

Example 3. Compute C = sin²20° + sin²70°.

  1. 20° + 70° = 90°, so the angles are complementary: sin 70° = cos 20°.
  2. Substitute: C = sin²20° + cos²20°.
  3. Apply sin²x + cos²x = 1:
C = 1

🔄 4. Angles differing by π: α and α + π (“tangent repeats every π”)

The terminal points of α and α + π are symmetric through the origin O: both coordinates change sign. So sine and cosine both change sign, while tangent and cotangent, being quotients of two numbers that both change sign, stay the same; that is also why tangent and cotangent have period π. Use these formulas for angles in quadrant III: write θ = π + α.

sin(α + π) = −sin α, cos(α + π) = −cos α
tan(α + π) = tan α, cot(α + π) = cot α

Example 4. Compute D = tan(7π/6) + sin(7π/6).

  1. Split 7π/6 = π/6 + π.
  2. Tangent stays: tan(7π/6) = √3/3.
  3. Sine changes sign: sin(7π/6) = −1/2.
  4. Add over a common denominator:
D = (2√3 − 3)/6

↪️ 5. Angles differing by π/2: α and α + π/2

Rotating the terminal point M(cos α; sin α) by 90° counter-clockwise gives the point (−sin α; cos α). Reading the coordinates: the cosine of the larger angle is −sin α and its sine is cos α. You can also derive this from the previous groups: α + π/2 = π − (π/2 − α), so apply the supplementary rule and then the complementary rule. Memory aid: the sine of the larger is the cosine of the smaller, the cosine of the larger is minus the sine of the smaller; tangent and cotangent swap and change sign.

sin(α + π/2) = cos α, cos(α + π/2) = −sin α
tan(α + π/2) = −cot α, cot(α + π/2) = −tan α

Example 5. Compute E = cos 120° · tan 120° using the π/2 formulas.

  1. Split 120° = 30° + 90°.
  2. Cosine of the larger is minus sine of the smaller: cos 120° = −1/2.
  3. Tangent becomes minus cotangent: tan 120° = −√3.
  4. Multiply:
E = √3/2

Check: cos x · tan x = sin x, and sin 120° = sin(180° − 60°) = sin 60° = √3/2, matching the result.

⚠️ Common mistakes

  1. Flipping every sign. Thinking “related angles always change sign” and writing cos(−α) = −cos α. Cosine is even, so it stays.
  2. Forgetting to swap functions for complementary angles and angles differing by π/2. sin(π/2 − α) is cos α, not sin α.
  3. Adding a minus sign to complementary angles. Complementary angles never change sign; the minus appears only for angles differing by π/2, for example cos(α + π/2) = −sin α.
  4. Mixing up periods. Tangent has period π but sine and cosine have period 2π: sin(α + π) = −sin α, not sin α.
  5. Removing turns wrongly from negative angles. −750° = 330° + (−3)·360°, so θ₀ = 330°, not 30°. Always check that 0° ≤ θ₀ < 360°.
  6. Choosing a non-acute α. For θ₀ = 210° write 210° = 180° + 30° to get the acute α = 30° before using the special-angle table.

🎯 Practice quiz: one question per related-angle group

Pick one answer for each question. The correct answer turns green, a wrong one turns red, and the worked solution appears right below with a ⚠️ Traps section explaining why the distractors, usually a wrong sign, are so tempting.

↔️ Opposite angles Question 1. The value of cos(−2π/3) is:

🪞 Supplementary angles Question 2. Simplifying A = sin(π − x) + cos(π − x) gives:

✖️ Complementary angles Question 3. Given cos α = 1/3 with 0 < α < π/2, the value of sin(π/2 − α) is:

🔄 Differing by π Question 4. The value of tan(7π/6) is:

↪️ Differing by π/2 Question 5. For every x where it is defined, tan(x + π/2) equals:

🏋️ Advanced practice: one exercise per group

Each exercise simplifies an expression that mixes several related angles. Try it yourself first, then open the solution to compare. Tip: substitute a concrete value such as x = π/6 into both the original expression and your result.

↔️ Opposite angles Exercise 1.

Simplify, for sin x ≠ 0 and cos x ≠ 0:

A = sin(−x)cot(−x) + cos(4π − x) + tan(−x)cos(−x) + sin x
Show the detailed solution
  1. Opposite angles: sin(−x) = −sin x, cot(−x) = −cot x, so sin(−x)cot(−x) = cos x.
  2. Remove two turns (4π) and use “cosine ignores the minus”: cos(4π − x) = cos x.
  3. tan(−x)cos(−x) = −sin x.
  4. Add up:
A = 2cos x

🪞 Supplementary angles Exercise 2.

Simplify, for cos x ≠ 0:

B = sin(π − x) + cos(π − x)tan(π − x) + cos(3π − x) + cos(−x)
Show the detailed solution
  1. Sine survives the supplement: sin(π − x) = sin x.
  2. Cosine and tangent both change sign, so their product does not: cos(π − x)tan(π − x) = sin x.
  3. Remove one turn 2π, then use the supplementary formula: cos(3π − x) = −cos x.
  4. Opposite angle: cos(−x) = cos x.
  5. Add up:
B = 2sin x

✖️ Complementary angles Exercise 3.

Compute the product of 89 factors:

C = tan 1° · tan 2° · … · tan 89°
Show the detailed solution
  1. Pair each angle k° with its complement (90 − k)°. Co-functions cross over: tan(90° − k°) = cot k°, so tan k° · tan(90° − k°) = 1.
  2. The 89 factors form 44 pairs (1° with 89°, 2° with 88°, …, 44° with 46°) plus the middle factor tan 45° = 1.
  3. Therefore:
C = 1

🔄 Differing by π Exercise 4.

Simplify, for sin x ≠ 0 and cos x ≠ 0:

D = [sin(π + x) + sin(x − π)] / [cos(3π + x)tan(x + 2π)]
Show the detailed solution
  1. Angles differing by π: sin(π + x) = −sin x.
  2. x − π = (x + π) − 2π, so sin(x − π) = −sin x. The numerator is −2sin x.
  3. Remove one turn: cos(3π + x) = −cos x. Tangent has period π: tan(x + 2π) = tan x. The denominator is −cos x tan x = −sin x.
  4. Divide:
D = 2

↪️ Differing by π/2 Exercise 5.

Simplify, for sin x ≠ 0 and cos x ≠ 0:

E = sin(x + π/2)cos(x − π/2) + cos(x + π/2)sin(x + 5π/2) + tan(x + π/2)tan x
Show the detailed solution
  1. Angles differing by π/2: sin(x + π/2) = cos x, cos(x + π/2) = −sin x, tan(x + π/2) = −cot x.
  2. Opposite, then complementary: cos(x − π/2) = cos(π/2 − x) = sin x.
  3. Remove one turn: sin(x + 5π/2) = sin(x + π/2) = cos x.
  4. Substitute:
E = −1

❓ Frequently asked questions (FAQ)

What are related angles?

Related angles are pairs whose sum or difference is special: opposite (α and −α), supplementary (α and π − α), complementary (α and π/2 − α), differing by π (α and α + π) and differing by π/2 (α and α + π/2). Their trigonometric values are equal or opposite, possibly with sine and cosine or tangent and cotangent swapped, which is how any angle is reduced to an acute one.

How do I remember which function changes sign?

Cosine ignores the minus: cos(−α) = cos α. Sine survives the supplement: sin(π − α) = sin α. Co-functions cross over for complementary angles, with no sign change. Tangent repeats every π: tan(α + π) = tan α. Every other function changes sign.

How do I reduce 2010° to an acute angle?

Remove 5 turns: 2010° = 210° + 5·360°. 210° is in quadrant III, so write 210° = 180° + 30° and use the formulas for angles differing by π. For example sin 2010° = sin 210° = −sin 30° = −1/2, and tan 2010° = tan 30° = √3/3.

Why is tan(α + π) = tan α but sin(α + π) = −sin α?

The terminal point of α + π is the image of the terminal point of α through the origin, so both sine and cosine change sign. Tangent is sine divided by cosine, a quotient of two numbers that both change sign, so it stays the same. That is why tangent and cotangent have period π while sine and cosine have period 2π.

Which angle formats does the tool accept?

Degrees such as 150, 225°, −750, 22.5 or 45/2; radians with π such as 7pi/6, 7π/6, −3pi/4 or 7/6pi; and decimal radians such as 2.5 when the unit is set to Radians or written as 2.5rad. An angle with π is always read as radians and an angle with ° is always degrees.

When is the result exact and when is it approximate?

When the acute angle α is a multiple of 15° (π/12), sin, cos, tan and cot are written exactly with surds such as √3/2 or (√6 − √2)/4. For other angles, for example 200° with α = 20°, the reduction steps are still exact but the final values are rounded to 4 decimal places and labelled “Approximate”.

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